Base | Representation |
---|---|
bin | 1010011110100100001101… |
… | …1101111101011011010011 |
3 | 1111210022201221010000112212 |
4 | 2213221003131331123103 |
5 | 3002221414424340443 |
6 | 40300153400142335 |
7 | 2266211100066554 |
oct | 247510335753323 |
9 | 44708657100485 |
10 | 11520234215123 |
11 | 3741781978747 |
12 | 13608471679ab |
13 | 65747962348a |
14 | 2bb821c0c32b |
15 | 14ea038c0618 |
hex | a7a4377d6d3 |
11520234215123 has 2 divisors, whose sum is σ = 11520234215124. Its totient is φ = 11520234215122.
The previous prime is 11520234215099. The next prime is 11520234215173. The reversal of 11520234215123 is 32151243202511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11520234215123 - 218 = 11520233952979 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11520234215123.
It is not a weakly prime, because it can be changed into another prime (11520234215173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760117107561 + 5760117107562.
It is an arithmetic number, because the mean of its divisors is an integer number (5760117107562).
Almost surely, 211520234215123 is an apocalyptic number.
11520234215123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520234215123 is an equidigital number, since it uses as much as digits as its factorization.
11520234215123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 11520234215123 its reverse (32151243202511), we get a palindrome (43671477417634).
The spelling of 11520234215123 in words is "eleven trillion, five hundred twenty billion, two hundred thirty-four million, two hundred fifteen thousand, one hundred twenty-three".
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