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11520653404313 is a prime number
BaseRepresentation
bin1010011110100101110001…
…1101000010100010011001
31111210100211010220001000102
42213221130131002202121
53002223244232414223
640300303132545145
72266224350122514
oct247513435024231
944710733801012
1011520653404313
11374197755a799
1213609436221b5
13657515423111
142bb861769d7b
1514ea2a5c4928
hexa7a5c742899

11520653404313 has 2 divisors, whose sum is σ = 11520653404314. Its totient is φ = 11520653404312.

The previous prime is 11520653404223. The next prime is 11520653404319. The reversal of 11520653404313 is 31340435602511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5860403363929 + 5660250040384 = 2420827^2 + 2379128^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11520653404313 is a prime.

It is not a weakly prime, because it can be changed into another prime (11520653404319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760326702156 + 5760326702157.

It is an arithmetic number, because the mean of its divisors is an integer number (5760326702157).

Almost surely, 211520653404313 is an apocalyptic number.

It is an amenable number.

11520653404313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11520653404313 is an equidigital number, since it uses as much as digits as its factorization.

11520653404313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 11520653404313 in words is "eleven trillion, five hundred twenty billion, six hundred fifty-three million, four hundred four thousand, three hundred thirteen".