Base | Representation |
---|---|
bin | 1010011110100101110001… |
… | …1101000010100010011001 |
3 | 1111210100211010220001000102 |
4 | 2213221130131002202121 |
5 | 3002223244232414223 |
6 | 40300303132545145 |
7 | 2266224350122514 |
oct | 247513435024231 |
9 | 44710733801012 |
10 | 11520653404313 |
11 | 374197755a799 |
12 | 13609436221b5 |
13 | 657515423111 |
14 | 2bb861769d7b |
15 | 14ea2a5c4928 |
hex | a7a5c742899 |
11520653404313 has 2 divisors, whose sum is σ = 11520653404314. Its totient is φ = 11520653404312.
The previous prime is 11520653404223. The next prime is 11520653404319. The reversal of 11520653404313 is 31340435602511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5860403363929 + 5660250040384 = 2420827^2 + 2379128^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11520653404313 is a prime.
It is not a weakly prime, because it can be changed into another prime (11520653404319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5760326702156 + 5760326702157.
It is an arithmetic number, because the mean of its divisors is an integer number (5760326702157).
Almost surely, 211520653404313 is an apocalyptic number.
It is an amenable number.
11520653404313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11520653404313 is an equidigital number, since it uses as much as digits as its factorization.
11520653404313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 11520653404313 in words is "eleven trillion, five hundred twenty billion, six hundred fifty-three million, four hundred four thousand, three hundred thirteen".
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