Base | Representation |
---|---|
bin | 10101011101011100… |
… | …00011101101110001 |
3 | 1002201221020211121101 |
4 | 22232232003231301 |
5 | 142043414302032 |
6 | 5143124124401 |
7 | 555335646463 |
oct | 125656035561 |
9 | 32657224541 |
10 | 11521244017 |
11 | 4982495178 |
12 | 2296536701 |
13 | 1117c0a16a |
14 | 7b41d6133 |
15 | 476701de7 |
hex | 2aeb83b71 |
11521244017 has 4 divisors (see below), whose sum is σ = 11521618420. Its totient is φ = 11520869616.
The previous prime is 11521244011. The next prime is 11521244047. The reversal of 11521244017 is 71044212511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10173546496 + 1347697521 = 100864^2 + 36711^2 .
It is a cyclic number.
It is not a de Polignac number, because 11521244017 - 211 = 11521241969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11521244011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136458 + ... + 204115.
It is an arithmetic number, because the mean of its divisors is an integer number (2880404605).
Almost surely, 211521244017 is an apocalyptic number.
It is an amenable number.
11521244017 is a deficient number, since it is larger than the sum of its proper divisors (374403).
11521244017 is an equidigital number, since it uses as much as digits as its factorization.
11521244017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 374402.
The product of its (nonzero) digits is 2240, while the sum is 28.
Adding to 11521244017 its reverse (71044212511), we get a palindrome (82565456528).
The spelling of 11521244017 in words is "eleven billion, five hundred twenty-one million, two hundred forty-four thousand, seventeen".
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