Base | Representation |
---|---|
bin | 11010001100100100110110… |
… | …000010110111001110010111 |
3 | 120002221021221020202110111020 |
4 | 122030210312002313032113 |
5 | 110100124023013412401 |
6 | 1045012150214012223 |
7 | 33160615365200325 |
oct | 3214446602671627 |
9 | 502837836673436 |
10 | 115213404435351 |
11 | 3378a8042185a2 |
12 | 10b09168047073 |
13 | 4c3976778b931 |
14 | 2064503b30d15 |
15 | d4be72097d36 |
hex | 68c9360b7397 |
115213404435351 has 16 divisors (see below), whose sum is σ = 154077857472000. Its totient is φ = 76579193978208.
The previous prime is 115213404435323. The next prime is 115213404435401. The reversal of 115213404435351 is 153534404312511.
115213404435351 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 115213404435351 - 219 = 115213403911063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115213404435751) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29423316 + ... + 33108281.
It is an arithmetic number, because the mean of its divisors is an integer number (9629866092000).
Almost surely, 2115213404435351 is an apocalyptic number.
115213404435351 is a deficient number, since it is larger than the sum of its proper divisors (38864453036649).
115213404435351 is a wasteful number, since it uses less digits than its factorization.
115213404435351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62533438.
The product of its (nonzero) digits is 432000, while the sum is 42.
Adding to 115213404435351 its reverse (153534404312511), we get a palindrome (268747808747862).
The spelling of 115213404435351 in words is "one hundred fifteen trillion, two hundred thirteen billion, four hundred four million, four hundred thirty-five thousand, three hundred fifty-one".
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