Base | Representation |
---|---|
bin | 10000110001000100011… |
… | …110110010111110110001 |
3 | 11002011000210212121022122 |
4 | 100301010132302332301 |
5 | 122334201220043103 |
6 | 2241151412044025 |
7 | 146146410521321 |
oct | 20610436627661 |
9 | 4064023777278 |
10 | 1152200159153 |
11 | 404710a5219a |
12 | 167379603615 |
13 | 84862603c04 |
14 | 3daa40b7281 |
15 | 1ee88594b38 |
hex | 10c447b2fb1 |
1152200159153 has 2 divisors, whose sum is σ = 1152200159154. Its totient is φ = 1152200159152.
The previous prime is 1152200159137. The next prime is 1152200159161. The reversal of 1152200159153 is 3519510022511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 815396358049 + 336803801104 = 902993^2 + 580348^2 .
It is a cyclic number.
It is not a de Polignac number, because 1152200159153 - 24 = 1152200159137 is a prime.
It is not a weakly prime, because it can be changed into another prime (1152200159353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576100079576 + 576100079577.
It is an arithmetic number, because the mean of its divisors is an integer number (576100079577).
Almost surely, 21152200159153 is an apocalyptic number.
It is an amenable number.
1152200159153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152200159153 is an equidigital number, since it uses as much as digits as its factorization.
1152200159153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 35.
The spelling of 1152200159153 in words is "one trillion, one hundred fifty-two billion, two hundred million, one hundred fifty-nine thousand, one hundred fifty-three".
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