Base | Representation |
---|---|
bin | 110101101001110111… |
… | …0001010000100011001 |
3 | 102000101222002120002111 |
4 | 1223103232022010121 |
5 | 3341433114222022 |
6 | 124533143032321 |
7 | 11216201253511 |
oct | 1532356120431 |
9 | 360358076074 |
10 | 115221242137 |
11 | 44957429661 |
12 | 1a3b743b6a1 |
13 | ab3313c6b1 |
14 | 58107d6841 |
15 | 2ee56a2477 |
hex | 1ad3b8a119 |
115221242137 has 2 divisors, whose sum is σ = 115221242138. Its totient is φ = 115221242136.
The previous prime is 115221242069. The next prime is 115221242161. The reversal of 115221242137 is 731242122511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91602470281 + 23618771856 = 302659^2 + 153684^2 .
It is a cyclic number.
It is not a de Polignac number, because 115221242137 - 27 = 115221242009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115221242099 and 115221242108.
It is not a weakly prime, because it can be changed into another prime (115221242237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57610621068 + 57610621069.
It is an arithmetic number, because the mean of its divisors is an integer number (57610621069).
Almost surely, 2115221242137 is an apocalyptic number.
It is an amenable number.
115221242137 is a deficient number, since it is larger than the sum of its proper divisors (1).
115221242137 is an equidigital number, since it uses as much as digits as its factorization.
115221242137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6720, while the sum is 31.
Adding to 115221242137 its reverse (731242122511), we get a palindrome (846463364648).
The spelling of 115221242137 in words is "one hundred fifteen billion, two hundred twenty-one million, two hundred forty-two thousand, one hundred thirty-seven".
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