1152240000001 has 4 divisors (see below), whose sum is σ = 1152242267904. Its totient is φ = 1152237732100.

The previous prime is 1152239999941. The next prime is 1152240000097. The reversal of 1152240000001 is 1000000422511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1152240000001 - 2¹⁵ = 1152239967233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1152240000001.

It is not an unprimeable number, because it can be changed into a prime (1152240004001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18696 + ... + 1518166.

It is an arithmetic number, because the mean of its divisors is an integer number (288060566976).

Almost surely, 2^{1152240000001} is an apocalyptic number.

It is an amenable number.

1152240000001 is a deficient number, since it is larger than the sum of its proper divisors (2267903).

1152240000001 is an equidigital number, since it uses as much as digits as its factorization.

1152240000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2267902.

The product of its (nonzero) digits is 80, while the sum is 16.

Adding to 1152240000001 its reverse (1000000422511), we get a palindrome (2152240422512).

The spelling of 1152240000001 in words is "one trillion, one hundred fifty-two billion, two hundred forty million, one", and thus it is an aban number.