Base | Representation |
---|---|
bin | 11010001100110100110011… |
… | …100011011110111110011011 |
3 | 120002222221011122002120211221 |
4 | 122030310303203132332123 |
5 | 110100414122341234230 |
6 | 1045024102550432511 |
7 | 33162063156432301 |
oct | 3214646343367633 |
9 | 502887148076757 |
10 | 115230542524315 |
11 | 33796aa9223489 |
12 | 10b1054b662737 |
13 | 4c3b26927058a |
14 | 206528bcb8271 |
15 | d4c62694a27a |
hex | 68cd338def9b |
115230542524315 has 32 divisors (see below), whose sum is σ = 143894376426240. Its totient is φ = 88512152217216.
The previous prime is 115230542524303. The next prime is 115230542524333. The reversal of 115230542524315 is 513425245032511.
It is a cyclic number.
It is not a de Polignac number, because 115230542524315 - 211 = 115230542522267 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 594233364 + ... + 594427246.
It is an arithmetic number, because the mean of its divisors is an integer number (4496699263320).
Almost surely, 2115230542524315 is an apocalyptic number.
115230542524315 is a deficient number, since it is larger than the sum of its proper divisors (28663833901925).
115230542524315 is a wasteful number, since it uses less digits than its factorization.
115230542524315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 240843.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 115230542524315 its reverse (513425245032511), we get a palindrome (628655787556826).
The spelling of 115230542524315 in words is "one hundred fifteen trillion, two hundred thirty billion, five hundred forty-two million, five hundred twenty-four thousand, three hundred fifteen".
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