Base | Representation |
---|---|
bin | 1010011110101110111100… |
… | …1001110011111111001011 |
3 | 1111210121011200002110222211 |
4 | 2213223233021303333023 |
5 | 3002243314320132411 |
6 | 40301351253125551 |
7 | 2266342344064216 |
oct | 247535711637713 |
9 | 44717150073884 |
10 | 11523114614731 |
11 | 3742a1a87a595 |
12 | 136130b9298b7 |
13 | 6578182c0945 |
14 | 2bba165a077d |
15 | 14eb216dc221 |
hex | a7aef273fcb |
11523114614731 has 2 divisors, whose sum is σ = 11523114614732. Its totient is φ = 11523114614730.
The previous prime is 11523114614663. The next prime is 11523114614741. The reversal of 11523114614731 is 13741641132511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11523114614731 - 27 = 11523114614603 is a prime.
It is a super-2 number, since 2×115231146147312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11523114614741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761557307365 + 5761557307366.
It is an arithmetic number, because the mean of its divisors is an integer number (5761557307366).
Almost surely, 211523114614731 is an apocalyptic number.
11523114614731 is a deficient number, since it is larger than the sum of its proper divisors (1).
11523114614731 is an equidigital number, since it uses as much as digits as its factorization.
11523114614731 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60480, while the sum is 40.
The spelling of 11523114614731 in words is "eleven trillion, five hundred twenty-three billion, one hundred fourteen million, six hundred fourteen thousand, seven hundred thirty-one".
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