Base | Representation |
---|---|
bin | 10000110001001011000… |
… | …111011100110011011001 |
3 | 11002011022120100021010221 |
4 | 100301023013130303121 |
5 | 122334413214321023 |
6 | 2241210430040041 |
7 | 146152231652425 |
oct | 20611307346331 |
9 | 4064276307127 |
10 | 1152311479513 |
11 | 404768875897 |
12 | 1673aa949021 |
13 | 8487c6ac24c |
14 | 3dab4bb3b85 |
15 | 1ee9323385d |
hex | 10c4b1dccd9 |
1152311479513 has 4 divisors (see below), whose sum is σ = 1152524127760. Its totient is φ = 1152098831268.
The previous prime is 1152311479499. The next prime is 1152311479531. The reversal of 1152311479513 is 3159741132511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1152311479513 - 213 = 1152311471321 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1152311479513.
It is not an unprimeable number, because it can be changed into a prime (1152311474513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106315995 + ... + 106326832.
It is an arithmetic number, because the mean of its divisors is an integer number (288131031940).
Almost surely, 21152311479513 is an apocalyptic number.
It is an amenable number.
1152311479513 is a deficient number, since it is larger than the sum of its proper divisors (212648247).
1152311479513 is an equidigital number, since it uses as much as digits as its factorization.
1152311479513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212648246.
The product of its digits is 113400, while the sum is 43.
The spelling of 1152311479513 in words is "one trillion, one hundred fifty-two billion, three hundred eleven million, four hundred seventy-nine thousand, five hundred thirteen".
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