Base | Representation |
---|---|
bin | 1010011110101111000001… |
… | …0100101110000000101011 |
3 | 1111210121020001001002221221 |
4 | 2213223300110232000223 |
5 | 3002243334332013201 |
6 | 40301353234042511 |
7 | 2266343003020033 |
oct | 247536024560053 |
9 | 44717201032857 |
10 | 11523134251051 |
11 | 3742a2a971655 |
12 | 1361316419437 |
13 | 65781c3a7677 |
14 | 2bba190328c3 |
15 | 14eb232ba4a1 |
hex | a7af052e02b |
11523134251051 has 2 divisors, whose sum is σ = 11523134251052. Its totient is φ = 11523134251050.
The previous prime is 11523134251001. The next prime is 11523134251073. The reversal of 11523134251051 is 15015243132511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11523134251051 - 27 = 11523134250923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11523134250998 and 11523134251016.
It is not a weakly prime, because it can be changed into another prime (11523134251001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5761567125525 + 5761567125526.
It is an arithmetic number, because the mean of its divisors is an integer number (5761567125526).
Almost surely, 211523134251051 is an apocalyptic number.
11523134251051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11523134251051 is an equidigital number, since it uses as much as digits as its factorization.
11523134251051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 11523134251051 its reverse (15015243132511), we get a palindrome (26538377383562).
The spelling of 11523134251051 in words is "eleven trillion, five hundred twenty-three billion, one hundred thirty-four million, two hundred fifty-one thousand, fifty-one".
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