115233161520049 has 2 divisors, whose sum is σ = 115233161520050. Its totient is φ = 115233161520048.

The previous prime is 115233161519999. The next prime is 115233161520073. The reversal of 115233161520049 is 940025161332511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60245849712400 + 54987311807649 = 7761820^2 + 7415343^2 .

It is an emirp because it is prime and its reverse (940025161332511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115233161520049 - 2²⁹ = 115232624649137 is a prime.

It is a super-3 number, since 3×115233161520049³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115233161519987 and 115233161520014.

It is not a weakly prime, because it can be changed into another prime (115233161520949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57616580760024 + 57616580760025.

It is an arithmetic number, because the mean of its divisors is an integer number (57616580760025).

Almost surely, 2^{115233161520049} is an apocalyptic number.

It is an amenable number.

115233161520049 is a deficient number, since it is larger than the sum of its proper divisors (1).

115233161520049 is an equidigital number, since it uses as much as digits as its factorization.

115233161520049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 43.

The spelling of 115233161520049 in words is "one hundred fifteen trillion, two hundred thirty-three billion, one hundred sixty-one million, five hundred twenty thousand, forty-nine".