Base | Representation |
---|---|
bin | 11010001100111000100001… |
… | …010000100100101001100111 |
3 | 120010000022110120020222201021 |
4 | 122030320201100210221213 |
5 | 110101000304304403411 |
6 | 1045030002411512011 |
7 | 33162264043151440 |
oct | 3214704120445147 |
9 | 503008416228637 |
10 | 115234530544231 |
11 | 3379876537490a |
12 | 10b11283158607 |
13 | 4c3b753559087 |
14 | 20655497d02c7 |
15 | d4c7abb05a71 |
hex | 68ce21424a67 |
115234530544231 has 16 divisors (see below), whose sum is σ = 133565818434048. Its totient is φ = 97370844228000.
The previous prime is 115234530544229. The next prime is 115234530544241. The reversal of 115234530544231 is 132445035432511.
It is not a de Polignac number, because 115234530544231 - 21 = 115234530544229 is a prime.
It is a super-3 number, since 3×1152345305442313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115234530544241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7801320 + ... + 17068381.
It is an arithmetic number, because the mean of its divisors is an integer number (8347863652128).
Almost surely, 2115234530544231 is an apocalyptic number.
115234530544231 is a deficient number, since it is larger than the sum of its proper divisors (18331287889817).
115234530544231 is an equidigital number, since it uses as much as digits as its factorization.
115234530544231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24879102.
The product of its (nonzero) digits is 864000, while the sum is 43.
Adding to 115234530544231 its reverse (132445035432511), we get a palindrome (247679565976742).
The spelling of 115234530544231 in words is "one hundred fifteen trillion, two hundred thirty-four billion, five hundred thirty million, five hundred forty-four thousand, two hundred thirty-one".
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