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11524139993 is a prime number
BaseRepresentation
bin10101011101110010…
…00110101111011001
31002202010200222010202
422232321012233121
5142100134434433
65143310151545
7555402400532
oct125671065731
932663628122
1011524139993
114984092a43
1222974b25b5
1311186b2362
147b474b689
15476ac4ee8
hex2aee46bd9

11524139993 has 2 divisors, whose sum is σ = 11524139994. Its totient is φ = 11524139992.

The previous prime is 11524139953. The next prime is 11524140029. The reversal of 11524139993 is 39993142511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7393764169 + 4130375824 = 85987^2 + 64268^2 .

It is a cyclic number.

It is not a de Polignac number, because 11524139993 - 214 = 11524123609 is a prime.

It is not a weakly prime, because it can be changed into another prime (11524139933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762069996 + 5762069997.

It is an arithmetic number, because the mean of its divisors is an integer number (5762069997).

Almost surely, 211524139993 is an apocalyptic number.

It is an amenable number.

11524139993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11524139993 is an equidigital number, since it uses as much as digits as its factorization.

11524139993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 262440, while the sum is 47.

The spelling of 11524139993 in words is "eleven billion, five hundred twenty-four million, one hundred thirty-nine thousand, nine hundred ninety-three".