115243331140131 has 32 divisors (see below), whose sum is σ = 155059477659648. Its totient is φ = 76129553969280.

The previous prime is 115243331140087. The next prime is 115243331140151. The reversal of 115243331140131 is 131041133342511.

It is a happy number.

It is not a de Polignac number, because 115243331140131 - 2⁴¹ = 113044307884579 is a prime.

It is a super-2 number, since 2×115243331140131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115243331140092 and 115243331140101.

It is not an unprimeable number, because it can be changed into a prime (115243331140151) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5005997401 + ... + 5006020421.

It is an arithmetic number, because the mean of its divisors is an integer number (4845608676864).

Almost surely, 2^{115243331140131} is an apocalyptic number.

115243331140131 is a deficient number, since it is larger than the sum of its proper divisors (39816146519517).

115243331140131 is a wasteful number, since it uses less digits than its factorization.

115243331140131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38851.

The product of its (nonzero) digits is 12960, while the sum is 33.

Adding to 115243331140131 its reverse (131041133342511), we get a palindrome (246284464482642).

The spelling of 115243331140131 in words is "one hundred fifteen trillion, two hundred forty-three billion, three hundred thirty-one million, one hundred forty thousand, one hundred thirty-one".