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115245313322353 is a prime number
BaseRepresentation
bin11010001101000010100011…
…111101100110110101110001
3120010001100022000221212112221
4122031002203331212311301
5110101134400202303403
61045034544400121041
733163125204231364
oct3215024375466561
9503040260855487
10115245313322353
11337a2298a27695
1210b13392306181
134c3c781479666
142065c8d8b80db
15d4cbdd587dbd
hex68d0a3f66d71

115245313322353 has 2 divisors, whose sum is σ = 115245313322354. Its totient is φ = 115245313322352.

The previous prime is 115245313322317. The next prime is 115245313322387. The reversal of 115245313322353 is 353223313542511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77329915950049 + 37915397372304 = 8793743^2 + 6157548^2 .

It is a cyclic number.

It is not a de Polignac number, because 115245313322353 - 213 = 115245313314161 is a prime.

It is not a weakly prime, because it can be changed into another prime (115245313320353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57622656661176 + 57622656661177.

It is an arithmetic number, because the mean of its divisors is an integer number (57622656661177).

Almost surely, 2115245313322353 is an apocalyptic number.

It is an amenable number.

115245313322353 is a deficient number, since it is larger than the sum of its proper divisors (1).

115245313322353 is an equidigital number, since it uses as much as digits as its factorization.

115245313322353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972000, while the sum is 43.

Adding to 115245313322353 its reverse (353223313542511), we get a palindrome (468468626864864).

The spelling of 115245313322353 in words is "one hundred fifteen trillion, two hundred forty-five billion, three hundred thirteen million, three hundred twenty-two thousand, three hundred fifty-three".