Base | Representation |
---|---|
bin | 11010001101000010100011… |
… | …111101100110110101110001 |
3 | 120010001100022000221212112221 |
4 | 122031002203331212311301 |
5 | 110101134400202303403 |
6 | 1045034544400121041 |
7 | 33163125204231364 |
oct | 3215024375466561 |
9 | 503040260855487 |
10 | 115245313322353 |
11 | 337a2298a27695 |
12 | 10b13392306181 |
13 | 4c3c781479666 |
14 | 2065c8d8b80db |
15 | d4cbdd587dbd |
hex | 68d0a3f66d71 |
115245313322353 has 2 divisors, whose sum is σ = 115245313322354. Its totient is φ = 115245313322352.
The previous prime is 115245313322317. The next prime is 115245313322387. The reversal of 115245313322353 is 353223313542511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77329915950049 + 37915397372304 = 8793743^2 + 6157548^2 .
It is a cyclic number.
It is not a de Polignac number, because 115245313322353 - 213 = 115245313314161 is a prime.
It is not a weakly prime, because it can be changed into another prime (115245313320353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57622656661176 + 57622656661177.
It is an arithmetic number, because the mean of its divisors is an integer number (57622656661177).
Almost surely, 2115245313322353 is an apocalyptic number.
It is an amenable number.
115245313322353 is a deficient number, since it is larger than the sum of its proper divisors (1).
115245313322353 is an equidigital number, since it uses as much as digits as its factorization.
115245313322353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 972000, while the sum is 43.
Adding to 115245313322353 its reverse (353223313542511), we get a palindrome (468468626864864).
The spelling of 115245313322353 in words is "one hundred fifteen trillion, two hundred forty-five billion, three hundred thirteen million, three hundred twenty-two thousand, three hundred fifty-three".
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