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115253043055001 is a prime number
BaseRepresentation
bin11010001101001001110000…
…101100001100100110011001
3120010002002020201210222100022
4122031021300230030212121
5110101301213010230001
61045042303403120225
733163520563665155
oct3215116054144631
9503062221728308
10115253043055001
11337a55a5189195
1210b1498ab13075
134c40413a02067
1420663c430c065
15d4cee1e9911b
hex68d270b0c999

115253043055001 has 2 divisors, whose sum is σ = 115253043055002. Its totient is φ = 115253043055000.

The previous prime is 115253043054991. The next prime is 115253043055037. The reversal of 115253043055001 is 100550340352511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93291644737600 + 21961398317401 = 9658760^2 + 4686299^2 .

It is a cyclic number.

It is not a de Polignac number, because 115253043055001 - 222 = 115253038860697 is a prime.

It is a super-2 number, since 2×1152530430550012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115253043355001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57626521527500 + 57626521527501.

It is an arithmetic number, because the mean of its divisors is an integer number (57626521527501).

Almost surely, 2115253043055001 is an apocalyptic number.

It is an amenable number.

115253043055001 is a deficient number, since it is larger than the sum of its proper divisors (1).

115253043055001 is an equidigital number, since it uses as much as digits as its factorization.

115253043055001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45000, while the sum is 35.

The spelling of 115253043055001 in words is "one hundred fifteen trillion, two hundred fifty-three billion, forty-three million, fifty-five thousand, one".