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11525316131 = 73974147289
BaseRepresentation
bin10101011101111011…
…00101111000100011
31002202012220201111102
422232331211320203
5142100440104011
65143351305015
7555415366520
oct125675457043
932665821442
1011525316131
11498481665a
12229797b16b
131118a047b4
147b4976147
15476c5873b
hex2aef65e23

11525316131 has 8 divisors (see below), whose sum is σ = 13204971360. Its totient is φ = 9853956288.

The previous prime is 11525316067. The next prime is 11525316133. The reversal of 11525316131 is 13161352511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11525316131 - 26 = 11525316067 is a prime.

It is a super-2 number, since 2×115253161312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11525316094 and 11525316103.

It is not an unprimeable number, because it can be changed into a prime (11525316133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2070866 + ... + 2076423.

It is an arithmetic number, because the mean of its divisors is an integer number (1650621420).

Almost surely, 211525316131 is an apocalyptic number.

11525316131 is a deficient number, since it is larger than the sum of its proper divisors (1679655229).

11525316131 is an equidigital number, since it uses as much as digits as its factorization.

11525316131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4147693.

The product of its digits is 2700, while the sum is 29.

Adding to 11525316131 its reverse (13161352511), we get a palindrome (24686668642).

The spelling of 11525316131 in words is "eleven billion, five hundred twenty-five million, three hundred sixteen thousand, one hundred thirty-one".

Divisors: 1 7 397 2779 4147289 29031023 1646473733 11525316131