Base | Representation |
---|---|
bin | 10101011101111011… |
… | …00101111000100011 |
3 | 1002202012220201111102 |
4 | 22232331211320203 |
5 | 142100440104011 |
6 | 5143351305015 |
7 | 555415366520 |
oct | 125675457043 |
9 | 32665821442 |
10 | 11525316131 |
11 | 498481665a |
12 | 229797b16b |
13 | 1118a047b4 |
14 | 7b4976147 |
15 | 476c5873b |
hex | 2aef65e23 |
11525316131 has 8 divisors (see below), whose sum is σ = 13204971360. Its totient is φ = 9853956288.
The previous prime is 11525316067. The next prime is 11525316133. The reversal of 11525316131 is 13161352511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11525316131 - 26 = 11525316067 is a prime.
It is a super-2 number, since 2×115253161312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11525316094 and 11525316103.
It is not an unprimeable number, because it can be changed into a prime (11525316133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2070866 + ... + 2076423.
It is an arithmetic number, because the mean of its divisors is an integer number (1650621420).
Almost surely, 211525316131 is an apocalyptic number.
11525316131 is a deficient number, since it is larger than the sum of its proper divisors (1679655229).
11525316131 is an equidigital number, since it uses as much as digits as its factorization.
11525316131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4147693.
The product of its digits is 2700, while the sum is 29.
Adding to 11525316131 its reverse (13161352511), we get a palindrome (24686668642).
The spelling of 11525316131 in words is "eleven billion, five hundred twenty-five million, three hundred sixteen thousand, one hundred thirty-one".
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