1152553413003 has 4 divisors (see below), whose sum is σ = 1536737884008. Its totient is φ = 768368942000.

The previous prime is 1152553412971. The next prime is 1152553413029. The reversal of 1152553413003 is 3003143552511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1152553413003 - 2⁵ = 1152553412971 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1152553413203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192092235498 + ... + 192092235503.

It is an arithmetic number, because the mean of its divisors is an integer number (384184471002).

Almost surely, 2^{1152553413003} is an apocalyptic number.

1152553413003 is a deficient number, since it is larger than the sum of its proper divisors (384184471005).

1152553413003 is an equidigital number, since it uses as much as digits as its factorization.

1152553413003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 384184471004.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 1152553413003 its reverse (3003143552511), we get a palindrome (4155696965514).

The spelling of 1152553413003 in words is "one trillion, one hundred fifty-two billion, five hundred fifty-three million, four hundred thirteen thousand, three".