Base | Representation |
---|---|
bin | 1010011110110111111101… |
… | …0111100001111111110001 |
3 | 1111210211102021211121012102 |
4 | 2213231333113201333301 |
5 | 3002313243214131121 |
6 | 40302431323510145 |
7 | 2266456323451112 |
oct | 247557727417761 |
9 | 44724367747172 |
10 | 11525534130161 |
11 | 3743a51601317 |
12 | 1361886088355 |
13 | 657b1265028c |
14 | 2bbba5a60209 |
15 | 14ec13d1a90b |
hex | a7b7f5e1ff1 |
11525534130161 has 2 divisors, whose sum is σ = 11525534130162. Its totient is φ = 11525534130160.
The previous prime is 11525534130109. The next prime is 11525534130167. The reversal of 11525534130161 is 16103143552511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10095012880225 + 1430521249936 = 3177265^2 + 1196044^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11525534130161 is a prime.
It is not a weakly prime, because it can be changed into another prime (11525534130167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762767065080 + 5762767065081.
It is an arithmetic number, because the mean of its divisors is an integer number (5762767065081).
Almost surely, 211525534130161 is an apocalyptic number.
It is an amenable number.
11525534130161 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525534130161 is an equidigital number, since it uses as much as digits as its factorization.
11525534130161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 38.
Adding to 11525534130161 its reverse (16103143552511), we get a palindrome (27628677682672).
The spelling of 11525534130161 in words is "eleven trillion, five hundred twenty-five billion, five hundred thirty-four million, one hundred thirty thousand, one hundred sixty-one".
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