Base | Representation |
---|---|
bin | 1010011110110111111101… |
… | …0111100010001011110011 |
3 | 1111210211102021211122020221 |
4 | 2213231333113202023303 |
5 | 3002313243214142211 |
6 | 40302431323513511 |
7 | 2266456323453262 |
oct | 247557727421363 |
9 | 44724367748227 |
10 | 11525534130931 |
11 | 3743a51601957 |
12 | 1361886088897 |
13 | 657b12650732 |
14 | 2bbba5a605d9 |
15 | 14ec13d1ac71 |
hex | a7b7f5e22f3 |
11525534130931 has 2 divisors, whose sum is σ = 11525534130932. Its totient is φ = 11525534130930.
The previous prime is 11525534130907. The next prime is 11525534130967. The reversal of 11525534130931 is 13903143552511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11525534130931 - 211 = 11525534128883 is a prime.
It is a super-2 number, since 2×115255341309312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11525534430931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5762767065465 + 5762767065466.
It is an arithmetic number, because the mean of its divisors is an integer number (5762767065466).
Almost surely, 211525534130931 is an apocalyptic number.
11525534130931 is a deficient number, since it is larger than the sum of its proper divisors (1).
11525534130931 is an equidigital number, since it uses as much as digits as its factorization.
11525534130931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243000, while the sum is 43.
The spelling of 11525534130931 in words is "eleven trillion, five hundred twenty-five billion, five hundred thirty-four million, one hundred thirty thousand, nine hundred thirty-one".
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