Base | Representation |
---|---|
bin | 10000110001011110111… |
… | …001101000000111010111 |
3 | 11002012011200220120122220 |
4 | 100301132321220013113 |
5 | 122341103202301101 |
6 | 2241303404153423 |
7 | 146163402150165 |
oct | 20613671500727 |
9 | 4065150816586 |
10 | 1152643400151 |
11 | 404919171771 |
12 | 167481b38873 |
13 | 849033a52a9 |
14 | 3db06cd6235 |
15 | 1eeb244a636 |
hex | 10c5ee681d7 |
1152643400151 has 32 divisors (see below), whose sum is σ = 1550919591936. Its totient is φ = 761426400000.
The previous prime is 1152643400149. The next prime is 1152643400159. The reversal of 1152643400151 is 1510043462511.
It is not a de Polignac number, because 1152643400151 - 21 = 1152643400149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1152643400159) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 472200091 + ... + 472202531.
It is an arithmetic number, because the mean of its divisors is an integer number (48466237248).
Almost surely, 21152643400151 is an apocalyptic number.
1152643400151 is a deficient number, since it is larger than the sum of its proper divisors (398276191785).
1152643400151 is a wasteful number, since it uses less digits than its factorization.
1152643400151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4783.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 1152643400151 its reverse (1510043462511), we get a palindrome (2662686862662).
The spelling of 1152643400151 in words is "one trillion, one hundred fifty-two billion, six hundred forty-three million, four hundred thousand, one hundred fifty-one".
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