Base | Representation |
---|---|
bin | 10101011110001000… |
… | …10011110011011011 |
3 | 1002202100020012001212 |
4 | 22233010103303123 |
5 | 142101412431313 |
6 | 5143453133335 |
7 | 555436352504 |
oct | 125704236333 |
9 | 32670205055 |
10 | 11527077083 |
11 | 4985809695 |
12 | 229848a24b |
13 | 11191a0192 |
14 | 7b4cb3bab |
15 | 476ea53a8 |
hex | 2af113cdb |
11527077083 has 2 divisors, whose sum is σ = 11527077084. Its totient is φ = 11527077082.
The previous prime is 11527077031. The next prime is 11527077127. The reversal of 11527077083 is 38077072511.
It is a strong prime.
It is an emirp because it is prime and its reverse (38077072511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11527077083 - 210 = 11527076059 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11527077083.
It is not a weakly prime, because it can be changed into another prime (11527077883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5763538541 + 5763538542.
It is an arithmetic number, because the mean of its divisors is an integer number (5763538542).
Almost surely, 211527077083 is an apocalyptic number.
11527077083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11527077083 is an equidigital number, since it uses as much as digits as its factorization.
11527077083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82320, while the sum is 41.
The spelling of 11527077083 in words is "eleven billion, five hundred twenty-seven million, seventy-seven thousand, eighty-three".
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