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1152941210081 is a prime number
BaseRepresentation
bin10000110001110000101…
…001101011100111100001
311002012221110021220002022
4100301300221223213201
5122342210422210311
62241353123231225
7146203646405543
oct20616051534741
94065843256068
101152941210081
11404a6128a781
12167545818515
138494ccb729b
143db34699693
151eecd6755db
hex10c70a6b9e1

1152941210081 has 2 divisors, whose sum is σ = 1152941210082. Its totient is φ = 1152941210080.

The previous prime is 1152941210063. The next prime is 1152941210117. The reversal of 1152941210081 is 1800121492511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 999982000081 + 152959210000 = 999991^2 + 391100^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1152941210081 is a prime.

It is a super-2 number, since 2×11529412100812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1152941210381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576470605040 + 576470605041.

It is an arithmetic number, because the mean of its divisors is an integer number (576470605041).

Almost surely, 21152941210081 is an apocalyptic number.

It is an amenable number.

1152941210081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1152941210081 is an equidigital number, since it uses as much as digits as its factorization.

1152941210081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 35.

The spelling of 1152941210081 in words is "one trillion, one hundred fifty-two billion, nine hundred forty-one million, two hundred ten thousand, eighty-one".