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11530614003153 = 371972787192169
BaseRepresentation
bin1010011111001010111000…
…1001101101010111010001
31111211022112022111212220120
42213302232021231113101
53002404144141100103
640305031351100453
72300026235612340
oct247625611552721
944738468455816
1011530614003153
113746119003063
121362863371729
13658441bc649b
142bc128593b57
1514ee0ec9d253
hexa7cae26d5d1

11530614003153 has 16 divisors (see below), whose sum is σ = 17659649589120. Its totient is φ = 6555475979136.

The previous prime is 11530614003127. The next prime is 11530614003221. The reversal of 11530614003153 is 35130041603511.

It is a happy number.

It is not a de Polignac number, because 11530614003153 - 26 = 11530614003089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11530614002153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1393591948 + ... + 1393600221.

It is an arithmetic number, because the mean of its divisors is an integer number (1103728099320).

Almost surely, 211530614003153 is an apocalyptic number.

It is an amenable number.

11530614003153 is a deficient number, since it is larger than the sum of its proper divisors (6129035585967).

11530614003153 is a wasteful number, since it uses less digits than its factorization.

11530614003153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2787192376.

The product of its (nonzero) digits is 16200, while the sum is 33.

Adding to 11530614003153 its reverse (35130041603511), we get a palindrome (46660655606664).

The spelling of 11530614003153 in words is "eleven trillion, five hundred thirty billion, six hundred fourteen million, three thousand, one hundred fifty-three".

Divisors: 1 3 7 21 197 591 1379 4137 2787192169 8361576507 19510345183 58531035549 549076857293 1647230571879 3843538001051 11530614003153