Base | Representation |
---|---|
bin | 1010011111001100110100… |
… | …1011010011101100100011 |
3 | 1111211100212120221200022021 |
4 | 2213303031023103230203 |
5 | 3002411230414003003 |
6 | 40305155143322311 |
7 | 2300045156112454 |
oct | 247631513235443 |
9 | 44740776850267 |
10 | 11531134516003 |
11 | 3746365900073 |
12 | 1362989750397 |
13 | 6584c59b125b |
14 | 2bc17776912b |
15 | 14ee408192bd |
hex | a7ccd2d3b23 |
11531134516003 has 2 divisors, whose sum is σ = 11531134516004. Its totient is φ = 11531134516002.
The previous prime is 11531134515983. The next prime is 11531134516051. The reversal of 11531134516003 is 30061543113511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11531134516003 - 213 = 11531134507811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11531134516003.
It is not a weakly prime, because it can be changed into another prime (11531134516063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765567258001 + 5765567258002.
It is an arithmetic number, because the mean of its divisors is an integer number (5765567258002).
Almost surely, 211531134516003 is an apocalyptic number.
11531134516003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11531134516003 is an equidigital number, since it uses as much as digits as its factorization.
11531134516003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 34.
Adding to 11531134516003 its reverse (30061543113511), we get a palindrome (41592677629514).
The spelling of 11531134516003 in words is "eleven trillion, five hundred thirty-one billion, one hundred thirty-four million, five hundred sixteen thousand, three".
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