Base | Representation |
---|---|
bin | 10000110001111011111… |
… | …111000110010111100011 |
3 | 11002020102201010020000022 |
4 | 100301323333012113203 |
5 | 122343103112432201 |
6 | 2241424035144055 |
7 | 146211445645466 |
oct | 20617377062743 |
9 | 4066381106008 |
10 | 1153131374051 |
11 | 405049664788 |
12 | 16759944502b |
13 | 84980509547 |
14 | 3db51a3b2dd |
15 | 1eee01da41b |
hex | 10c7bfc65e3 |
1153131374051 has 2 divisors, whose sum is σ = 1153131374052. Its totient is φ = 1153131374050.
The previous prime is 1153131374047. The next prime is 1153131374189. The reversal of 1153131374051 is 1504731313511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1153131374051 - 22 = 1153131374047 is a prime.
It is not a weakly prime, because it can be changed into another prime (1153131374011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576565687025 + 576565687026.
It is an arithmetic number, because the mean of its divisors is an integer number (576565687026).
Almost surely, 21153131374051 is an apocalyptic number.
1153131374051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1153131374051 is an equidigital number, since it uses as much as digits as its factorization.
1153131374051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 35.
Adding to 1153131374051 its reverse (1504731313511), we get a palindrome (2657862687562).
The spelling of 1153131374051 in words is "one trillion, one hundred fifty-three billion, one hundred thirty-one million, three hundred seventy-four thousand, fifty-one".
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