Base | Representation |
---|---|
bin | 10000110010000001100… |
… | …101001011111011001001 |
3 | 11002020200020202022212110 |
4 | 100302001211023323021 |
5 | 122343301130304421 |
6 | 2241441231132533 |
7 | 146213665561041 |
oct | 20620145137311 |
9 | 4066606668773 |
10 | 1153225244361 |
11 | 405097649953 |
12 | 167604974149 |
13 | 84996ab4cc8 |
14 | 3db602b4721 |
15 | 1eee857da76 |
hex | 10c8194bec9 |
1153225244361 has 4 divisors (see below), whose sum is σ = 1537633659152. Its totient is φ = 768816829572.
The previous prime is 1153225244359. The next prime is 1153225244401. The reversal of 1153225244361 is 1634425223511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1153225244361 - 21 = 1153225244359 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1153225244761) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192204207391 + ... + 192204207396.
It is an arithmetic number, because the mean of its divisors is an integer number (384408414788).
Almost surely, 21153225244361 is an apocalyptic number.
It is an amenable number.
1153225244361 is a deficient number, since it is larger than the sum of its proper divisors (384408414791).
1153225244361 is an equidigital number, since it uses as much as digits as its factorization.
1153225244361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 384408414790.
The product of its digits is 172800, while the sum is 39.
The spelling of 1153225244361 in words is "one trillion, one hundred fifty-three billion, two hundred twenty-five million, two hundred forty-four thousand, three hundred sixty-one".
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