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1153313156044 = 22741189755573
BaseRepresentation
bin10000110010000110110…
…100100010101111001100
311002020220101011201000201
4100302012310202233030
5122343441131443134
62241454051303244
7146216114035240
oct20620664425714
94066811151021
101153313156044
11405132234235
1216762a2aab24
13849ac08555a
143db6bc3a420
1520001146914
hex10c86d22bcc

1153313156044 has 12 divisors (see below), whose sum is σ = 2306626312144. Its totient is φ = 494277066864.

The previous prime is 1153313156029. The next prime is 1153313156119. The reversal of 1153313156044 is 4406513133511.

1153313156044 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 1153313155994 and 1153313156012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20594877759 + ... + 20594877814.

Almost surely, 21153313156044 is an apocalyptic number.

1153313156044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

1153313156044 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1153313156044 is a wasteful number, since it uses less digits than its factorization.

1153313156044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41189755584 (or 41189755582 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 1153313156044 its reverse (4406513133511), we get a palindrome (5559826289555).

The spelling of 1153313156044 in words is "one trillion, one hundred fifty-three billion, three hundred thirteen million, one hundred fifty-six thousand, forty-four".

Divisors: 1 2 4 7 14 28 41189755573 82379511146 164759022292 288328289011 576656578022 1153313156044