Base | Representation |
---|---|
bin | 10101011110110111… |
… | …01111110101111001 |
3 | 1002202202210100021021 |
4 | 22233123233311321 |
5 | 142110001034431 |
6 | 5144232542441 |
7 | 555542522503 |
oct | 125733576571 |
9 | 32682710237 |
10 | 11533221241 |
11 | 4989225903 |
12 | 229a551a21 |
13 | 111a541989 |
14 | 7b5a32d73 |
15 | 4777bab11 |
hex | 2af6efd79 |
11533221241 has 4 divisors (see below), whose sum is σ = 11534016400. Its totient is φ = 11532426084.
The previous prime is 11533221229. The next prime is 11533221251. The reversal of 11533221241 is 14212233511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14212233511 = 7 ⋅2030319073.
It is a cyclic number.
It is not a de Polignac number, because 11533221241 - 27 = 11533221113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11533221211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375411 + ... + 404968.
It is an arithmetic number, because the mean of its divisors is an integer number (2883504100).
Almost surely, 211533221241 is an apocalyptic number.
It is an amenable number.
11533221241 is a deficient number, since it is larger than the sum of its proper divisors (795159).
11533221241 is an equidigital number, since it uses as much as digits as its factorization.
11533221241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 795158.
The product of its digits is 1440, while the sum is 25.
Adding to 11533221241 its reverse (14212233511), we get a palindrome (25745454752).
The spelling of 11533221241 in words is "eleven billion, five hundred thirty-three million, two hundred twenty-one thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •