115341025433 has 4 divisors (see below), whose sum is σ = 116221491408. Its totient is φ = 114460559460.

The previous prime is 115341025427. The next prime is 115341025469. The reversal of 115341025433 is 334520143511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115341025433 - 2¹⁶ = 115340959897 is a prime.

It is a super-3 number, since 3×115341025433³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115341025433.

It is not an unprimeable number, because it can be changed into a prime (115341025403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 440232791 + ... + 440233052.

It is an arithmetic number, because the mean of its divisors is an integer number (29055372852).

Almost surely, 2^115341025433 is an apocalyptic number.

It is an amenable number.

115341025433 is a deficient number, since it is larger than the sum of its proper divisors (880465975).

115341025433 is an equidigital number, since it uses as much as digits as its factorization.

115341025433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 880465974.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 115341025433 its reverse (334520143511), we get a palindrome (449861168944).

The spelling of 115341025433 in words is "one hundred fifteen billion, three hundred forty-one million, twenty-five thousand, four hundred thirty-three".