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115343611217 is a prime number
BaseRepresentation
bin110101101101100000…
…0111101010101010001
3102000201111100112220122
41223123000331111101
53342210431024332
6124553233520025
711222215342622
oct1533300752521
9360644315818
10115343611217
1144a0a50932a
121a430413015
13ab525b5a33
145822b6ba49
1530012c4c12
hex1adb03d551

115343611217 has 2 divisors, whose sum is σ = 115343611218. Its totient is φ = 115343611216.

The previous prime is 115343611193. The next prime is 115343611249. The reversal of 115343611217 is 712116343511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112472366161 + 2871245056 = 335369^2 + 53584^2 .

It is an emirp because it is prime and its reverse (712116343511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115343611217 is a prime.

It is not a weakly prime, because it can be changed into another prime (115343611717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57671805608 + 57671805609.

It is an arithmetic number, because the mean of its divisors is an integer number (57671805609).

Almost surely, 2115343611217 is an apocalyptic number.

It is an amenable number.

115343611217 is a deficient number, since it is larger than the sum of its proper divisors (1).

115343611217 is an equidigital number, since it uses as much as digits as its factorization.

115343611217 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 35.

Adding to 115343611217 its reverse (712116343511), we get a palindrome (827459954728).

The spelling of 115343611217 in words is "one hundred fifteen billion, three hundred forty-three million, six hundred eleven thousand, two hundred seventeen".