Base | Representation |
---|---|
bin | 10000110010010010110… |
… | …000100000010010000010 |
3 | 11002021102100000101000111 |
4 | 100302102300200102002 |
5 | 122344343414032002 |
6 | 2241530003541534 |
7 | 146224065216652 |
oct | 20622260402202 |
9 | 4067370011014 |
10 | 1153513424002 |
11 | 40522528a545 |
12 | 16768538a8aa |
13 | 84a117047c4 |
14 | 3db8a68c362 |
15 | 20013a053d7 |
hex | 10c92c20482 |
1153513424002 has 4 divisors (see below), whose sum is σ = 1730270136006. Its totient is φ = 576756712000.
The previous prime is 1153513423987. The next prime is 1153513424033. The reversal of 1153513424002 is 2004243153511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 614403577921 + 539109846081 = 783839^2 + 734241^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 288378355999 + ... + 288378356002.
Almost surely, 21153513424002 is an apocalyptic number.
1153513424002 is a deficient number, since it is larger than the sum of its proper divisors (576756712004).
1153513424002 is an equidigital number, since it uses as much as digits as its factorization.
1153513424002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576756712003.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1153513424002 its reverse (2004243153511), we get a palindrome (3157756577513).
It can be divided in two parts, 115351 and 3424002, that added together give a palindrome (3539353).
The spelling of 1153513424002 in words is "one trillion, one hundred fifty-three billion, five hundred thirteen million, four hundred twenty-four thousand, two".
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