Base | Representation |
---|---|
bin | 11010001110100101010111… |
… | …100001101000010010100011 |
3 | 120010102111010202100200211001 |
4 | 122032211113201220102203 |
5 | 110104404134201232433 |
6 | 1045155412015132431 |
7 | 33203602231413202 |
oct | 3216452741502243 |
9 | 503374122320731 |
10 | 115351405102243 |
11 | 3383328aa80122 |
12 | 10b2ba60214117 |
13 | 4c4978b07ac8b |
14 | 206b0759d9239 |
15 | d5084c4d957d |
hex | 68e9578684a3 |
115351405102243 has 2 divisors, whose sum is σ = 115351405102244. Its totient is φ = 115351405102242.
The previous prime is 115351405102207. The next prime is 115351405102267. The reversal of 115351405102243 is 342201504153511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115351405102243 - 217 = 115351404971171 is a prime.
It is not a weakly prime, because it can be changed into another prime (115351405402243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57675702551121 + 57675702551122.
It is an arithmetic number, because the mean of its divisors is an integer number (57675702551122).
Almost surely, 2115351405102243 is an apocalyptic number.
115351405102243 is a deficient number, since it is larger than the sum of its proper divisors (1).
115351405102243 is an equidigital number, since it uses as much as digits as its factorization.
115351405102243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 115351405102243 its reverse (342201504153511), we get a palindrome (457552909255754).
The spelling of 115351405102243 in words is "one hundred fifteen trillion, three hundred fifty-one billion, four hundred five million, one hundred two thousand, two hundred forty-three".
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