1153540313 has 4 divisors (see below), whose sum is σ = 1153832628. Its totient is φ = 1153248000.

The previous prime is 1153540307. The next prime is 1153540319. The reversal of 1153540313 is 3130453511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3130453511 = 173 ⋅18095107.

It is an interprime number because it is at equal distance from previous prime (1153540307) and next prime (1153540319).

It can be written as a sum of positive squares in 2 ways, for example, as 79798489 + 1073741824 = 8933^2 + 32768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1153540313 is a prime.

It is a super-2 number, since 2×1153540313² = 2661310507432275938, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1153540319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140156 + ... + 148157.

It is an arithmetic number, because the mean of its divisors is an integer number (288458157).

Almost surely, 2^1153540313 is an apocalyptic number.

It is an amenable number.

1153540313 is a deficient number, since it is larger than the sum of its proper divisors (292315).

1153540313 is an equidigital number, since it uses as much as digits as its factorization.

1153540313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 292314.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 1153540313 is about 33963.8088706199. The cubic root of 1153540313 is about 1048.7635674313.

Adding to 1153540313 its reverse (3130453511), we get a palindrome (4283993824).

The spelling of 1153540313 in words is "one billion, one hundred fifty-three million, five hundred forty thousand, three hundred thirteen".