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11536357414753 is a prime number
BaseRepresentation
bin1010011111100000010001…
…1111000101011101100001
31111211212100120202102110201
42213320010133011131201
53003002424444233003
640311421320225201
72300321456035513
oct247700437053541
944755316672421
1011536357414753
1137485a6010216
1213639a690b201
13658b48a83aa2
142bc51128dbb3
151501490eeb1d
hexa7e047c5761

11536357414753 has 2 divisors, whose sum is σ = 11536357414754. Its totient is φ = 11536357414752.

The previous prime is 11536357414733. The next prime is 11536357414789. The reversal of 11536357414753 is 35741475363511.

11536357414753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8537891149089 + 2998466265664 = 2921967^2 + 1731608^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11536357414753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11536357414694 and 11536357414703.

It is not a weakly prime, because it can be changed into another prime (11536357414723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5768178707376 + 5768178707377.

It is an arithmetic number, because the mean of its divisors is an integer number (5768178707377).

Almost surely, 211536357414753 is an apocalyptic number.

It is an amenable number.

11536357414753 is a deficient number, since it is larger than the sum of its proper divisors (1).

11536357414753 is an equidigital number, since it uses as much as digits as its factorization.

11536357414753 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15876000, while the sum is 55.

The spelling of 11536357414753 in words is "eleven trillion, five hundred thirty-six billion, three hundred fifty-seven million, four hundred fourteen thousand, seven hundred fifty-three".