Base | Representation |
---|---|
bin | 10101011111100111… |
… | …01001110100110001 |
3 | 1002210012120201201021 |
4 | 22233303221310301 |
5 | 142113102104144 |
6 | 5145015135441 |
7 | 555650013205 |
oct | 125763516461 |
9 | 32705521637 |
10 | 11539488049 |
11 | 4991816191 |
12 | 22a0674581 |
13 | 111b92724b |
14 | 7b67c4b05 |
15 | 478107884 |
hex | 2afce9d31 |
11539488049 has 4 divisors (see below), whose sum is σ = 11937401460. Its totient is φ = 11141574640.
The previous prime is 11539488043. The next prime is 11539488083. The reversal of 11539488049 is 94088493511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6121497600 + 5417990449 = 78240^2 + 73607^2 .
It is a cyclic number.
It is not a de Polignac number, because 11539488049 - 213 = 11539479857 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11539487987 and 11539488005.
It is not an unprimeable number, because it can be changed into a prime (11539488043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198956662 + ... + 198956719.
It is an arithmetic number, because the mean of its divisors is an integer number (2984350365).
Almost surely, 211539488049 is an apocalyptic number.
It is an amenable number.
11539488049 is a deficient number, since it is larger than the sum of its proper divisors (397913411).
11539488049 is an equidigital number, since it uses as much as digits as its factorization.
11539488049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 397913410.
The product of its (nonzero) digits is 1244160, while the sum is 52.
The spelling of 11539488049 in words is "eleven billion, five hundred thirty-nine million, four hundred eighty-eight thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •