115402017552001 has 2 divisors, whose sum is σ = 115402017552002. Its totient is φ = 115402017552000.

The previous prime is 115402017551959. The next prime is 115402017552013. The reversal of 115402017552001 is 100255710204511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96366911722225 + 19035105829776 = 9816665^2 + 4362924^2 .

It is a cyclic number.

It is not a de Polignac number, because 115402017552001 - 2²¹ = 115402015454849 is a prime.

It is not a weakly prime, because it can be changed into another prime (115402017552071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701008776000 + 57701008776001.

It is an arithmetic number, because the mean of its divisors is an integer number (57701008776001).

Almost surely, 2^{115402017552001} is an apocalyptic number.

It is an amenable number.

115402017552001 is a deficient number, since it is larger than the sum of its proper divisors (1).

115402017552001 is an equidigital number, since it uses as much as digits as its factorization.

115402017552001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14000, while the sum is 34.

Adding to 115402017552001 its reverse (100255710204511), we get a palindrome (215657727756512).

The spelling of 115402017552001 in words is "one hundred fifteen trillion, four hundred two billion, seventeen million, five hundred fifty-two thousand, one".