Base | Representation |
---|---|
bin | 11010001111010101100011… |
… | …001011000010101111011101 |
3 | 120010121102200020220200002020 |
4 | 122033111203023002233131 |
5 | 110111231112332143141 |
6 | 1045235245400050353 |
7 | 33210413251646334 |
oct | 3217254313025735 |
9 | 503542606820066 |
10 | 115403140115421 |
11 | 33853219050264 |
12 | 10b39a9a1639b9 |
13 | 4c51614406002 |
14 | 206d782926d1b |
15 | d51d7934c266 |
hex | 68f5632c2bdd |
115403140115421 has 16 divisors (see below), whose sum is σ = 161984815304640. Its totient is φ = 72879220627200.
The previous prime is 115403140115359. The next prime is 115403140115423. The reversal of 115403140115421 is 124511041304511.
It is not a de Polignac number, because 115403140115421 - 210 = 115403140114397 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115403140115423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96247980 + ... + 97439621.
It is an arithmetic number, because the mean of its divisors is an integer number (10124050956540).
Almost surely, 2115403140115421 is an apocalyptic number.
It is an amenable number.
115403140115421 is a deficient number, since it is larger than the sum of its proper divisors (46581675189219).
115403140115421 is a wasteful number, since it uses less digits than its factorization.
115403140115421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193698076.
The product of its (nonzero) digits is 9600, while the sum is 33.
Adding to 115403140115421 its reverse (124511041304511), we get a palindrome (239914181419932).
The spelling of 115403140115421 in words is "one hundred fifteen trillion, four hundred three billion, one hundred forty million, one hundred fifteen thousand, four hundred twenty-one".
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