11540320041331 has 4 divisors (see below), whose sum is σ = 11540787720912. Its totient is φ = 11539852361752.

The previous prime is 11540320041319. The next prime is 11540320041337. The reversal of 11540320041331 is 13314002304511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11540320041331 - 2¹⁹ = 11540319517043 is a prime.

It is a super-2 number, since 2×11540320041331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11540320041331.

It is not an unprimeable number, because it can be changed into a prime (11540320041337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233802775 + ... + 233852128.

It is an arithmetic number, because the mean of its divisors is an integer number (2885196930228).

Almost surely, 2^{11540320041331} is an apocalyptic number.

11540320041331 is a deficient number, since it is larger than the sum of its proper divisors (467679581).

11540320041331 is an equidigital number, since it uses as much as digits as its factorization.

11540320041331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467679580.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 11540320041331 its reverse (13314002304511), we get a palindrome (24854322345842).

The spelling of 11540320041331 in words is "eleven trillion, five hundred forty billion, three hundred twenty million, forty-one thousand, three hundred thirty-one".