115403403 has 4 divisors (see below), whose sum is σ = 153871208. Its totient is φ = 76935600.

The previous prime is 115403401. The next prime is 115403417. The reversal of 115403403 is 304304511.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 115403403 - 2¹ = 115403401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115403403.

It is not an unprimeable number, because it can be changed into a prime (115403401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19233898 + ... + 19233903.

It is an arithmetic number, because the mean of its divisors is an integer number (38467802).

Almost surely, 2^115403403 is an apocalyptic number.

115403403 is a deficient number, since it is larger than the sum of its proper divisors (38467805).

115403403 is an equidigital number, since it uses as much as digits as its factorization.

115403403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38467804.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 115403403 is about 10742.5975908995. The cubic root of 115403403 is about 486.8623658329.

Adding to 115403403 its reverse (304304511), we get a palindrome (419707914).

The spelling of 115403403 in words is "one hundred fifteen million, four hundred three thousand, four hundred three".