Base | Representation |
---|---|
bin | 10101011111101110… |
… | …10111011100000001 |
3 | 1002210021102011210002 |
4 | 22233313113130001 |
5 | 142113324230223 |
6 | 5145052045345 |
7 | 555661205543 |
oct | 125767273401 |
9 | 32707364702 |
10 | 11540461313 |
11 | 4992320437 |
12 | 22a0a63855 |
13 | 111bba8244 |
14 | 7b6999693 |
15 | 47824ae28 |
hex | 2afdd7701 |
11540461313 has 2 divisors, whose sum is σ = 11540461314. Its totient is φ = 11540461312.
The previous prime is 11540461279. The next prime is 11540461327. The reversal of 11540461313 is 31316404511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11539700929 + 760384 = 107423^2 + 872^2 .
It is a cyclic number.
It is not a de Polignac number, because 11540461313 - 216 = 11540395777 is a prime.
It is not a weakly prime, because it can be changed into another prime (11540461913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770230656 + 5770230657.
It is an arithmetic number, because the mean of its divisors is an integer number (5770230657).
Almost surely, 211540461313 is an apocalyptic number.
It is an amenable number.
11540461313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11540461313 is an equidigital number, since it uses as much as digits as its factorization.
11540461313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 11540461313 its reverse (31316404511), we get a palindrome (42856865824).
The spelling of 11540461313 in words is "eleven billion, five hundred forty million, four hundred sixty-one thousand, three hundred thirteen".
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