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115413497 is a prime number
BaseRepresentation
bin1101110000100…
…01000111111001
322001011121112222
412320101013321
5214021212442
615241413425
72600666333
oct670210771
9261147488
10115413497
115a169961
123279a275
131abac414
1411484453
15a1eb8d2
hex6e111f9

115413497 has 2 divisors, whose sum is σ = 115413498. Its totient is φ = 115413496.

The previous prime is 115413479. The next prime is 115413559. The reversal of 115413497 is 794314511.

Together with previous prime (115413479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113720896 + 1692601 = 10664^2 + 1301^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115413497 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115413437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57706748 + 57706749.

It is an arithmetic number, because the mean of its divisors is an integer number (57706749).

Almost surely, 2115413497 is an apocalyptic number.

It is an amenable number.

115413497 is a deficient number, since it is larger than the sum of its proper divisors (1).

115413497 is an equidigital number, since it uses as much as digits as its factorization.

115413497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15120, while the sum is 35.

The square root of 115413497 is about 10743.0673925095. The cubic root of 115413497 is about 486.8765602307.

The spelling of 115413497 in words is "one hundred fifteen million, four hundred thirteen thousand, four hundred ninety-seven".