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115442555030441 is a prime number
BaseRepresentation
bin11010001111111010010000…
…011111000000101110101001
3120010202012102011000210212122
4122033322100133000232221
5110112402323041433231
61045305324434321025
733213310063131122
oct3217722037005651
9503665364023778
10115442555030441
1133868a048082a1
1210b4565a129175
134c552561b2732
142071641511049
15d52dd47b077b
hex68fe907c0ba9

115442555030441 has 2 divisors, whose sum is σ = 115442555030442. Its totient is φ = 115442555030440.

The previous prime is 115442555030437. The next prime is 115442555030507. The reversal of 115442555030441 is 144030555244511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92198788080400 + 23243766950041 = 9602020^2 + 4821179^2 .

It is a cyclic number.

It is not a de Polignac number, because 115442555030441 - 22 = 115442555030437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115442555030392 and 115442555030401.

It is not a weakly prime, because it can be changed into another prime (115442555030041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57721277515220 + 57721277515221.

It is an arithmetic number, because the mean of its divisors is an integer number (57721277515221).

Almost surely, 2115442555030441 is an apocalyptic number.

It is an amenable number.

115442555030441 is a deficient number, since it is larger than the sum of its proper divisors (1).

115442555030441 is an equidigital number, since it uses as much as digits as its factorization.

115442555030441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960000, while the sum is 44.

The spelling of 115442555030441 in words is "one hundred fifteen trillion, four hundred forty-two billion, five hundred fifty-five million, thirty thousand, four hundred forty-one".