Base | Representation |
---|---|
bin | 10101100000001100… |
… | …11010000000110001 |
3 | 1002210112211111011011 |
4 | 22300012122000301 |
5 | 142120331412032 |
6 | 5145312350521 |
7 | 556036546366 |
oct | 126006320061 |
9 | 32715744134 |
10 | 11544404017 |
11 | 4994573673 |
12 | 22a2245441 |
13 | 111c9589c3 |
14 | 7b730446d |
15 | 478779247 |
hex | 2b019a031 |
11544404017 has 2 divisors, whose sum is σ = 11544404018. Its totient is φ = 11544404016.
The previous prime is 11544403987. The next prime is 11544404021. The reversal of 11544404017 is 71040444511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7177308961 + 4367095056 = 84719^2 + 66084^2 .
It is a cyclic number.
It is not a de Polignac number, because 11544404017 - 231 = 9396920369 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11544404017.
It is not a weakly prime, because it can be changed into another prime (11544404087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772202008 + 5772202009.
It is an arithmetic number, because the mean of its divisors is an integer number (5772202009).
Almost surely, 211544404017 is an apocalyptic number.
It is an amenable number.
11544404017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11544404017 is an equidigital number, since it uses as much as digits as its factorization.
11544404017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8960, while the sum is 31.
Adding to 11544404017 its reverse (71040444511), we get a palindrome (82584848528).
The spelling of 11544404017 in words is "eleven billion, five hundred forty-four million, four hundred four thousand, seventeen".
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