Base | Representation |
---|---|
bin | 1010100000010100011000… |
… | …0100000111101011110011 |
3 | 1111220012110020020121100212 |
4 | 2220011012010013223303 |
5 | 3003220100142402430 |
6 | 40322053142134335 |
7 | 2301325153500434 |
oct | 250050604075363 |
9 | 44805406217325 |
10 | 11550342544115 |
11 | 3753522281971 |
12 | 136664a4213ab |
13 | 65a26728716b |
14 | 2bd07a7b548b |
15 | 1506b6c96b95 |
hex | a8146107af3 |
11550342544115 has 32 divisors (see below), whose sum is σ = 14689511179200. Its totient is φ = 8703648253440.
The previous prime is 11550342544093. The next prime is 11550342544121. The reversal of 11550342544115 is 51144524305511.
It is not a de Polignac number, because 11550342544115 - 26 = 11550342544051 is a prime.
It is a super-2 number, since 2×115503425441152 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4051505 + ... + 6286125.
It is an arithmetic number, because the mean of its divisors is an integer number (459047224350).
Almost surely, 211550342544115 is an apocalyptic number.
11550342544115 is a deficient number, since it is larger than the sum of its proper divisors (3139168635085).
11550342544115 is a wasteful number, since it uses less digits than its factorization.
11550342544115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2235527.
The product of its (nonzero) digits is 240000, while the sum is 41.
Adding to 11550342544115 its reverse (51144524305511), we get a palindrome (62694866849626).
The spelling of 11550342544115 in words is "eleven trillion, five hundred fifty billion, three hundred forty-two million, five hundred forty-four thousand, one hundred fifteen".
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