Base | Representation |
---|---|
bin | 10101100000111100… |
… | …01110111100010011 |
3 | 1002210222120211012201 |
4 | 22300132032330103 |
5 | 142123431301011 |
6 | 5150054304031 |
7 | 556143622546 |
oct | 126036167423 |
9 | 32728524181 |
10 | 11550650131 |
11 | 499804a449 |
12 | 22a4358017 |
13 | 1121034a27 |
14 | 7b808c85d |
15 | 4790aecc1 |
hex | 2b078ef13 |
11550650131 has 2 divisors, whose sum is σ = 11550650132. Its totient is φ = 11550650130.
The previous prime is 11550650063. The next prime is 11550650171. The reversal of 11550650131 is 13105605511.
It is a strong prime.
It is an emirp because it is prime and its reverse (13105605511) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11550650131 is a prime.
It is a super-2 number, since 2×115506501312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11550650131.
It is not a weakly prime, because it can be changed into another prime (11550650171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775325065 + 5775325066.
It is an arithmetic number, because the mean of its divisors is an integer number (5775325066).
Almost surely, 211550650131 is an apocalyptic number.
11550650131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11550650131 is an equidigital number, since it uses as much as digits as its factorization.
11550650131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2250, while the sum is 28.
The spelling of 11550650131 in words is "eleven billion, five hundred fifty million, six hundred fifty thousand, one hundred thirty-one".
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