Base | Representation |
---|---|
bin | 11010010000111011000010… |
… | …011010010010100100100111 |
3 | 120010222211221200222121000220 |
4 | 122100323002122102210213 |
5 | 110120022301201132333 |
6 | 1045401310504335423 |
7 | 33221321551541625 |
oct | 3220730232224447 |
9 | 503884850877026 |
10 | 115512112130343 |
11 | 338954589a2a25 |
12 | 10b57030774573 |
13 | 4c5b98c947c06 |
14 | 2074b5d396515 |
15 | d54b060868b3 |
hex | 690ec2692927 |
115512112130343 has 16 divisors (see below), whose sum is σ = 154203848257536. Its totient is φ = 76914227149760.
The previous prime is 115512112130227. The next prime is 115512112130447. The reversal of 115512112130343 is 343031211215511.
It is a cyclic number.
It is not a de Polignac number, because 115512112130343 - 28 = 115512112130087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115512112130543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 429532603 + ... + 429801443.
It is an arithmetic number, because the mean of its divisors is an integer number (9637740516096).
Almost surely, 2115512112130343 is an apocalyptic number.
115512112130343 is a deficient number, since it is larger than the sum of its proper divisors (38691736127193).
115512112130343 is a wasteful number, since it uses less digits than its factorization.
115512112130343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 442854.
The product of its (nonzero) digits is 10800, while the sum is 33.
Adding to 115512112130343 its reverse (343031211215511), we get a palindrome (458543323345854).
The spelling of 115512112130343 in words is "one hundred fifteen trillion, five hundred twelve billion, one hundred twelve million, one hundred thirty thousand, three hundred forty-three".
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