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115522410025513 is a prime number
BaseRepresentation
bin11010010001000100101000…
…001101101001001000101001
3120011000211112101021212111201
4122101010220031221020221
5110120204343431304023
61045410132412124201
733222135004315621
oct3221045015511051
9504024471255451
10115522410025513
1133899862883a97
1210b59025466661
134c5c9412770ca
142075458d01881
15d5500a189bad
hex691128369229

115522410025513 has 2 divisors, whose sum is σ = 115522410025514. Its totient is φ = 115522410025512.

The previous prime is 115522410025439. The next prime is 115522410025541. The reversal of 115522410025513 is 315520014225511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94588015055769 + 20934394969744 = 9725637^2 + 4575412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115522410025513 is a prime.

It is not a weakly prime, because it can be changed into another prime (115522410025573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57761205012756 + 57761205012757.

It is an arithmetic number, because the mean of its divisors is an integer number (57761205012757).

Almost surely, 2115522410025513 is an apocalyptic number.

It is an amenable number.

115522410025513 is a deficient number, since it is larger than the sum of its proper divisors (1).

115522410025513 is an equidigital number, since it uses as much as digits as its factorization.

115522410025513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60000, while the sum is 37.

The spelling of 115522410025513 in words is "one hundred fifteen trillion, five hundred twenty-two billion, four hundred ten million, twenty-five thousand, five hundred thirteen".