Base | Representation |
---|---|
bin | 11010010001010011001101… |
… | …001101110100011011100011 |
3 | 120011002022221021112020202211 |
4 | 122101103031031310123203 |
5 | 110120433423140324212 |
6 | 1045421241542222551 |
7 | 33223230625242556 |
oct | 3221231515643343 |
9 | 504068837466684 |
10 | 115538063214307 |
11 | 338a5465682458 |
12 | 10b60073724a57 |
13 | 4c612672226b6 |
14 | 2076101b9669d |
15 | d556244c69a7 |
hex | 6914cd3746e3 |
115538063214307 has 2 divisors, whose sum is σ = 115538063214308. Its totient is φ = 115538063214306.
The previous prime is 115538063214283. The next prime is 115538063214311. The reversal of 115538063214307 is 703412360835511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115538063214307 - 219 = 115538062690019 is a prime.
It is not a weakly prime, because it can be changed into another prime (115538063214397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57769031607153 + 57769031607154.
It is an arithmetic number, because the mean of its divisors is an integer number (57769031607154).
Almost surely, 2115538063214307 is an apocalyptic number.
115538063214307 is a deficient number, since it is larger than the sum of its proper divisors (1).
115538063214307 is an equidigital number, since it uses as much as digits as its factorization.
115538063214307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1814400, while the sum is 49.
The spelling of 115538063214307 in words is "one hundred fifteen trillion, five hundred thirty-eight billion, sixty-three million, two hundred fourteen thousand, three hundred seven".
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